这个 strrchr() 函数查找字符串中最后出现的字符。它返回一个指向字符串中最后一次出现的指针。终止的空字符被认为是C字符串的一部分。因此,也可以定位它来检索指向字符串结尾的指针。定义见 cstring 头文件。 语法:
null
const char* strrchr( const char* str, int ch ) or char* strrchr( char* str, int ch )
参数: 该函数采用两个强制参数,如下所述:
- str: 指定指向要搜索的以null结尾的字符串的指针。
- 中国: 指定要搜索的字符。
返回值: 函数返回一个指针,指向 中国 如果 中国 找到了。如果未找到,则返回空指针。
以下程序说明了上述功能:
项目1:
// C++ program to illustrate // the strrchr() function #include <bits/stdc++.h> using namespace std; int main() { // Storing it in string array char string[] = "Geeks for Geeks" ; // The character we've to search for char character = 'k' ; // Storing in a pointer ptr char * ptr = strrchr (string, character); // ptr-string gives the index location if (ptr) cout << "Last position of " << character << " in " << string << " is " << ptr - string; // If the character we're searching is not present in the array else cout << character << " is not present " << string << endl; return 0; } |
输出:
Last position of k in Geeks for Geeks is 13
项目2:
// C++ program to illustrate // the strrchr() function #include <bits/stdc++.h> using namespace std; int main() { // Storing it in string array char string[] = "Geeks for Geeks" ; char * ptr; // The character we've to search for char character = 'z' ; // Storing in a pointer ptr ptr = strrchr (string, character); // ptr-string gives the index location if (ptr) cout << "Last position of " << character << " in " << string << " is " << ptr - string; // If the character we're searching // is not present in the array else cout << character << " is not present in " << string << endl; return 0; } |
输出:
z is not present in Geeks for Geeks
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