C++中的ReMeReRead（）-yiteyi-C++库

此函数还用于返回参数中提到的2个浮点数的余数（模数）。计算出的商是四舍五入的。 余数=数字–rquot*denom 其中rquot是：number/denom的结果，向最近的整数值四舍五入（一半情况向偶数四舍五入）。

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语法：

double remainder(double a, double b)float remainder(float a, float b)long double remainder(long double a, long double b)Parameter:a and b are the values of numerator and denominator.Return:The remainder() function returns the floating point remainder of numerator/denominator rounded to nearest.

错误或异常： 必须同时给出两个参数，否则会出现错误—— 调用“余数（）”时没有匹配的函数 这样地。 #代码1

CPP

                         // CPP program to demonstrate                       
                         // remainder() function                       
                         #include <cmath>                       
                         #include <iostream>                       
           
                         using                                     namespace                                     std;                       
           
                         int                                     main()                       
                         {                       
                                                 double                                     a, b;                       
                                                 double                                     answer;                       
           
                                                 a = 50.35;                       
                                                 b = -4.1;                       
           
                                                 // here quotient is -12.2805 and rounded to nearest value then                       
                                                 // rquot = -12.                       
                                                 // remainder = 50.35 – (-12 * -4.1)                       
                                                 answer = remainder(a, b);                       
           
                                                 cout <<                                     "Remainder of "                                     << a <<                                     "/"                                     << b <<                                     " is "                                     << answer << endl;                       
           
                                                 a = 16.80;                       
                                                 b = 3.5;                       
           
                                                 // here quotient is 4.8 and rounded to nearest value then                       
                                                 // rquot = -5.                       
                                                 // remainder = 16.80 – (5 * 3.5)                       
                                                 answer = remainder(a, b);                       
           
                                                 cout <<                                     "Remainder of "                                     << a <<                                     "/"                                     << b <<                                     " is "                                     << answer << endl;                       
           
                                                 a = 16.80;                       
                                                 b = 0;                       
                                                 answer = remainder(a, b);                       
                                                 cout <<                                     "Remainder of "                                     << a <<                                     "/"                                     << b <<                                     " is "                                     << answer << endl;                       
           
                                                 return                                     0;                       
                         }                       

输出：

Remainder of 50.35/-4.1 is 1.15Remainder of 16.8/3.5 is -0.7Remainder of 16.8/0 is -nan

#代码2

CPP

                         // CPP program to demonstrate                       
                         // remainder() function                       
                         #include <cmath>                       
                         #include <iostream>                       
           
                         using                                     namespace                                     std;                       
           
                         int                                     main()                       
                         {                       
                                                 int                                     a = 50;                       
                                                 double                                     b = 41.35, answer;                       
           
                                                 answer = remainder(a, b);                       
                                                 cout <<                                     "Remainder of "                                     << a <<                                     "/"                                     << b <<                                     " = "                                     << answer << endl;                       
           
                                                 return                                     0;                       
                         }                       

输出：

Remainder of 50/41.35 = 8.65

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